7n+2[3(1-n)-2(1+2)]=14

Solution for 7n+2[3(1-n)-2(1+2)]=14 equation:

Simplifying
7n + 2[3(1 + -1n) + -2(1 + 2)] = 14
7n + 2[(1 * 3 + -1n * 3) + -2(1 + 2)] = 14
7n + 2[(3 + -3n) + -2(1 + 2)] = 14

Combine like terms: 1 + 2 = 3
7n + 2[3 + -3n + -2(3)] = 14

Multiply -2 * 3
7n + 2[3 + -3n + -6] = 14

Reorder the terms:
7n + 2[3 + -6 + -3n] = 14

Combine like terms: 3 + -6 = -3
7n + 2[-3 + -3n] = 14
7n + [-3 * 2 + -3n * 2] = 14
7n + [-6 + -6n] = 14

Reorder the terms:
-6 + 7n + -6n = 14

Combine like terms: 7n + -6n = 1n
-6 + 1n = 14

Solving
-6 + 1n = 14

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 1n = 14 + 6

Combine like terms: -6 + 6 = 0
0 + 1n = 14 + 6
1n = 14 + 6

Combine like terms: 14 + 6 = 20
1n = 20

Divide each side by '1'.
n = 20

Simplifying
n = 20